Applies abstract interpretation using different abstract domains (intervals, octagons, polyhedra, sign, congruence) to statically analyze program variables and infer invariants, value ranges, and relationships. Use when analyzing program properties, inferring loop invariants, detecting potential errors, or understanding variable relationships through static analysis.
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This skill applies abstract interpretation to statically analyze programs using various abstract domains. It infers invariants, value ranges, and relationships between variables without executing the code. Different domains offer different trade-offs between precision and efficiency.
Analysis Workflow
Follow these steps to analyze programs with abstract domains:
1. Select Appropriate Domain(s)
Choose based on analysis goals:
Interval Domain:
Use for: Range analysis, bounds checking, array indexing
Precision: Low to medium
Cost: Very efficient
Example: Determine if x ∈ [0, 100]
Sign Domain:
Use for: Sign analysis, division by zero detection
Precision: Low
Cost: Very efficient
Example: Determine if x is positive, negative, or zero
Congruence Domain:
Use for: Modular arithmetic, alignment analysis
Precision: Medium (for specific patterns)
Cost: Efficient
Example: Determine if x ≡ 0 (mod 4)
Octagon Domain:
Use for: Relational analysis, loop invariants with simple relationships
Precision: Medium to high
Cost: Moderate (O(n³) operations)
Example: Infer x ≤ y + 5, x + y ≤ 10
Polyhedra Domain:
Use for: Complex linear relationships, precise invariants
Precision: High
Cost: Expensive (exponential worst-case)
Example: Infer 2x + 3y ≤ z + 10
Reduced Product:
Use for: Combining strengths of multiple domains
Precision: Higher than individual domains
Cost: Sum of component costs
Example: Intervals × Congruence for precise range with modular constraints
2. Initialize Abstract State
Set initial values for program entry:
Constants: Exact values (e.g., x = 5 → x ∈ [5, 5])
Inputs: Top element (e.g., user input → x ∈ [-∞, +∞])
Uninitialized: Bottom element (unreachable)
Example:
int x = 0; // x ∈ [0, 0]
int y = input(); // y ∈ [-∞, +∞]
3. Apply Transfer Functions
For each statement, compute abstract semantics:
Assignment (x = e):
Evaluate expression e in abstract domain
Update abstract state for x
Condition (assume c):
Refine abstract state based on condition
Intersect with constraint
Join (control flow merge):
Compute least upper bound of incoming states
Used after if-else, at loop headers
Example (Intervals):
x = y + 5; // If y ∈ [a, b], then x ∈ [a+5, b+5]
assume(x > 10); // If x ∈ [a, b], then x ∈ [max(a, 11), b]
4. Handle Loops with Widening
For loops, apply widening to ensure termination:
Compute first iteration
Compute second iteration
Apply widening operator (∇)
Check for convergence
Continue until fixpoint reached
Example:
int x = 0;
while (x < 100) {
x = x + 1;
}
Iteration 0: x ∈ [0, 0]
Iteration 1: x ∈ [0, 1]
Widening: x ∈ [0, +∞]
Refine with condition: x ∈ [0, 99] in loop
Exit: x ∈ [100, 100]
5. Refine with Narrowing (Optional)
Apply narrowing to improve precision:
Iterate a few more times (typically 1-3)
Use narrowing operator (△)
Refine over-approximations from widening
6. Extract Invariants
Identify inferred properties:
Value ranges for each variable
Relationships between variables
Loop invariants
Preconditions for safe operations
Report format:
Variable: abstract value
Invariants: logical formulas
Safety properties: bounds checks, division by zero, etc.
Analysis Examples
Example 1: Range Analysis with Intervals
Code:
int x = 0;
int y = 100;
while (x < 10) {
x = x + 1;
y = y - 1;
}
// What are the values of x and y here?
Analysis (Interval Domain):
Entry: x ∈ [0, 0], y ∈ [100, 100]
Loop iterations with widening:
Iter 0: x ∈ [0, 0], y ∈ [100, 100]
Iter 1: x ∈ [0, 1], y ∈ [99, 100]
Widening: x ∈ [0, +∞], y ∈ [-∞, 100]
Refine with x < 10: x ∈ [0, 9], y ∈ [-∞, 100]
Narrowing: y ∈ [91, 100]
Exit: x ∈ [10, 10], y ∈ [90, 90]
Inferred Invariants:
Loop: x ∈ [0, 9], y ∈ [91, 100]
Exit: x = 10, y = 90
Implicit: x + y = 100 (not captured by intervals alone)
Example 2: Relational Analysis with Octagons
Code:
int x = 0;
int y = 0;
while (x < 10) {
x = x + 1;
y = y + 1;
}
Analysis (Octagon Domain):
Entry: x = 0, y = 0, x - y = 0
Loop iterations:
Maintains x - y = 0 throughout
x ∈ [0, 10], y ∈ [0, 10]
Exit: x = 10, y = 10, x = y
Inferred Invariants:
x = y (captured by octagon)
x ∈ [0, 10], y ∈ [0, 10]
Advantage over Intervals:
Intervals would only infer x ∈ [0, 10], y ∈ [0, 10] but miss the relationship x = y.
Example 3: Linear Relationships with Polyhedra
Code:
int x = 0, y = 0, z = 0;
while (x < 10) {
x = x + 1;
y = y + 2;
z = x + y;
}
Analysis (Polyhedra Domain):
Entry: x = 0, y = 0, z = 0
Loop iterations:
Infers: y = 2x, z = x + y, z = 3x
x ∈ [0, 10]
Exit: x = 10, y = 20, z = 30
Inferred Invariants:
y = 2x
z = x + y
z = 3x
x ∈ [0, 10]
Advantage over Octagons:
Polyhedra can express y = 2x, which octagons cannot.
Example 4: Modular Arithmetic with Congruence
Code:
int sum = 0;
for (int i = 0; i < 100; i++) {
sum = sum + 3;
}
Analysis (Congruence Domain):
Entry: sum ≡ 0 (mod 3), i ≡ 0 (mod 1)
Loop: sum ≡ 0 (mod 3) maintained
Exit: sum ≡ 0 (mod 3)
Analysis (Interval Domain):
Exit: sum ∈ [0, 300]
Combined (Reduced Product):
sum ∈ [0, 300] and sum ≡ 0 (mod 3)
Refined: sum ∈ {0, 3, 6, 9, ..., 297, 300}
Exact: sum = 300
Inferred Invariants:
sum is always divisible by 3
sum ∈ [0, 300]
Example 5: Division by Zero Detection with Sign
Code:
int x = read_input();
int y = x * x;
int z = 100 / y; // Safe?
Analysis (Sign Domain):
x: ⊤ (unknown sign)
y = x * x: ≥0 (non-negative)
Problem: y could be 0 if x = 0
Division 100 / y: potential division by zero
Analysis (Interval Domain):
x: [-∞, +∞]
y: [0, +∞]
Problem: 0 ∈ [0, +∞]
Division 100 / y: potential division by zero
Inferred Property:
Unsafe: Division by zero possible when x = 0
Example 6: Array Bounds Checking
Code:
int arr[10];
int i = 0;
while (i < 10) {
arr[i] = 0; // Safe?
i = i + 1;
}
Analysis (Interval Domain):
Loop: i ∈ [0, 9]
Array access: arr[i] where i ∈ [0, 9]
Array bounds: [0, 9]
Safe: i always within bounds
Inferred Property:
No array bounds violation
Example 7: Nested Loops with Octagons
Code:
int i = 0, j = 0;
while (i < 10) {
j = 0;
while (j < i) {
j = j + 1;
}
i = i + 1;
}
Analysis (Octagon Domain):
Outer loop: i ∈ [0, 10]
Inner loop: j ∈ [0, i], j ≤ i
Exit: i = 10, j = 9, j ≤ i
Inferred Invariants:
j ≤ i (relational invariant)
i ∈ [0, 10]
j ∈ [0, 9]
Domain Comparison
| Domain | Precision | Cost | Relationships | Best For |