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Symphony MCP Server

local only

Symphony runs on your own machine — the client starts it, so there is no endpoint to ping. Last commit 5 Nov 2026.

Inspect and administer a configured Symphony installation through its qxctl contracts.

—
Installs / week
not published
1
Stars
0 open issues
5 Nov 2026
Last commit
from GitHub
AGPL-3.0
License
Python

What the code does

We read the source, 1 d ago · rules 995398eba69f

Capabilities

What this server is able to do. For an MCP server this is often the job itself — a terminal server runs commands because that is what it is for. Listed so you know what you are plugging in, not as an accusation.

subprocess.run([sys.executable,str(Path(__file__).with_name('test_package_container.py')),

Is this your server and something here is wrong? Tell us — corrections are free and do not require a plan.

This code can reach further than it looks

We found places where it runs commands, builds paths or queries from values it is given. None of that is a flaw by itself — it becomes one when the code changes, and code changes quietly between releases. We re-read it on every one.

Three servers free · no card

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Symphony — questions

Answers built from our own checks of this server.

Why is there no uptime for Symphony?
Symphony runs on your own machine over stdio — there is no network address to reach, so uptime cannot be measured for it by anyone.
Is Symphony open source?
Yes — it is published under the AGPL-3.0 licence, written in Python and 1 stars on GitHub. The source link is on this page, so you can read exactly what it does with your data before you connect it.